# Line slope calculator 4x+5y=40

**Straight line given by points A[0; 8] and B[5; 4]**

## Calculation:

**Slope-intercept form of line:**y = -0.8x+8

**Canonical form of the line equation:**4x+5y-40 = 0

**Parametric form of the line equation:**

x = 5t

y = -4t+8 ; t ∈ R

**Slope:**m = -0.8

**Slope angle of line: φ =**-38°39'35″ = -0.6747 rad

**X intercept:**x

_{0}= 10

**Y intercept:**y

_{0}= q = 8

**Distance line from the origin:**d

_{0}= 6.247

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(5; -4)

**Normal vector: n =**(4; 5)

**Midpoint of the segment AB: M =**[2.5; 6]

**Perpendicular Bisector equation:**5x-4y+11.5 = 0

**Vector OA = (0; 8) ; |OA| = 8**

**Vector OB = (5; 4) ; |OB| = 6.4031**

**Scalar product OA .OB = 32**

**Angle ∠ AOB = 51°20'25″ = 0.8961 rad**